How to find directories containing only files older than X days?

Question

I need to delete directories that only contain files (created/modified) older than X days.

I tried this, but it will only show files from today and not recursively...

for d in *; do   
  find "$d" -mindepth 1 -mtime -180 -print -quit | | grep -q . ||     
  echo rm -rf "$d";
done

Answer 1

You want "to delete directories that only contain files older than X days".

Here's one way of handling it:

• For each directory in turn, starting from leaf nodes:
• Count the number of its child directories; skip if non-zero
• Count the number of its non-directory items; skip if zero
• Count the number of its files matching your criterion (age)
• Delete the directory if the two file counts are the same

This solution requires GNU find or an alternate version that understands -mindepth, -maxdepth, and printf.

This particular example sets your X to 180 (days).

days=180
find ./* -depth -type d -exec sh -c '
    [ -z "'"$days"'" ] && exit 1
    printf "Considering directory: %s\n" "$1"
dirs=$(find "$1" -mindepth 1 -maxdepth 1 -type d -print | xargs)
if [ -n "$dirs" ]
then
    printf "Found child directories: (%s)\n" "$dirs"
    exit 0
fi

all=$(find "$1" -maxdepth 1 ! -type d -printf x | wc -c)
got=$(find "$1" -maxdepth 1 -type f -mtime +'"$days"' -printf x | wc -c)
printf "Found %d item(s) and matched %d\n" $all $got

if [ $all -gt 0 ] && [ $all -eq $got ]
then
    printf "Delete directory: %s\n" "$1"
    : rm -rf "$1"
fi

' _ {} ;

The seemingly strange quoting around the two uses of the variable $days is to ensure that although the rest of the script is enclosed in single quotes, the variable is enclosed in double-quotes so that its value can be determined. It may be more easily understood as '..start of script..' "$variable" '..remainder of script..', except that we have no spaces between the ending of one type of quotes and the start of the other.

Remove the printf statements if you want the code to run silently. Remove the colon (:) in front of the rm -rf when you are ready to execute the delete action.

Answer 2

Assuming you want the shallowest directories that don't contain (at any level) non-directory files not older than 180 days (if both ./a/b and ./a don't contain recent files, only report ./a as ./a/b is part of that), that would be a variation on Listing only shallowest directories containing no files, all the way down, so you could use the same approach as my answer there if on a GNU system:

find . -type d -print0 -o -mtime -180 -printf 'f/%h\0' |
  LC_ALL=C sort -zru |
  LC_ALL=C awk -F/ -v RS='\0' '
    function parent(path) {
      sub("/[^/]*$", "", path)
      return path
    }
    $1 == "f" {
      sep = path = ""
      for (i = 2; i <= NF; i++) {
        black[path = path sep $i]
        sep = FS
      }
      next
    }
    ! ($0 in black) && ($0 == "." || parent($0) in black)'

Where instead of painting black the directories that have any non-directory file, we paint black the ones that have any non-directory file not older than 180 days.

Or a variation which removes directories from an array when a recent file is found:

find . -type d -printf '%p/\0' -o -mtime -180 -printf '%h/f\0' |
  LC_ALL=C sort -zu |
  LC_ALL=C awk -F/ -v RS='\0' '
    function parent(path) {
      sub("[^/]+/?$", "", path)
      return path
    }
    /\/$/ {dir[$0]; next}
    {
      path = ""
      for (i = 1; i <= NF; i++)
        delete dir[path = path $i FS]
    }
    END {
      for (path in dir) if (! (parent(path) in dir)) print path
    }'

If you want both ./a and ./a/b above (not only the shallowest), it becomes simpler:

find . -type d -printf '%p/\0' -o -mtime -180 -printf '%h/f\0' |
  LC_ALL=C sort -zu |
  LC_ALL=C awk -F/ -v RS='\0' '
    /\/$/ {dir[$0]; next}
    {
      path = ""
      for (i = 1; i <= NF; i++)
        delete dir[path = path $i FS]
    }
    END {
      for (path in dir) print path
    }'

If you want to delete them, add a -v ORS='\0' to awk to print them NUL-delimited, and pipe to xargs -r0 rm -rf, but beware that if ./ is returned (if there's no recent file anywhere in the current directory), most rm implementations will refuse to do anything¹.

Since those approaches run find and traverse the whole directory tree only once, they're more efficient than more naive approaches that crawl the contents of each directory for recent files.

One such less efficient approach in zsh:

print -rC1 -- **/*(ND/^e['()(($#)) $REPLY/**/*(NDm-180Y1^/)'])

(won't include ., though you could add it to the list with {.,**/*}(...))

If it's only the subdirectories of the current directory that you want to consider, then that approach becomes more efficient (as the Y1 above stops at the first match) as well as being shorter/simpler:

print -rC1 -- *(ND/^e['()(($#)) $REPLY/**/*(NDm-180Y1^/)'])

---

^{¹ as a work around for the fact that the expansion of .* in some shells includes . and .. and could be catastrophic with rm -rf .*. The rm builtin of zsh (a shell that doesn't have that misfeature), which you enable with zmodload zsh/files, will accept rm -rf ./ and empty the current working directory.}