Split/extract street name from street number

Question

I have some addresses.csv in this formats

Street 1
Street 10
Street 100
Street 1000
Straße 1b
Straße1b
Street 1 B
Street, 1B
The Street 1B
The-Street 1B
The'Street 1B
The&Street 1B
The Str. 1B
Street 1-3
Street 1 - 3
Street 1A-3B
Street 1A -3 B
Super's Street-Str., 1 - 1000B

Is there a way to seperate/extract all street names and street numbers?

output-names.csv

Street
Street
Street
Street
Straße
Straße
Street
Street
The Street
The-Street
The'Street
The&Street
The Str.
Street
Street
Street
Street
Super's Street-Str.

output-numbers.csv

1
10
100
1000
1b
1b
1 B
1B
1B
1B
1B
1B
1B
1-3
1 - 3
1A-3B
1A -3 B
1 - 1000B

I have found a solution that I want to share here:

Answer 1

My solution is

1. checking if the address-format is valid

if [[ ${var_street_and_number} =~ ^[[:alpha:][:space:]\.\'\&\-]+[,]?[[:space:]]?[0-9]{1,4}[[:space:]]?[a-zA-Z]?[[:space:]]?[-]?[[:space:]]?[0-9]{0,4}[[:space:]]?[a-zA-Z]?$ ]];
    then
    echo "Adress is format is valid :)";
else
    echo "Adress is format is invalid \!";
fi;

The variable var_street_and_number should be one line with the street name + number

If you have a file with many streets and numbers (= many lines) you can use :

while read line; do
    if [[ ${line} =...
done < addresses.csv

2. If the adress format is valid you can use sed

sed 's/[,]\{0,1\}[[:space:]]\{0,1\}[[:digit:]].*$//' address.csv > output-name.csv
sed 's/^[^[:digit:]]*//' address.csv > output-number.csv