Require a file in the current directory without setting load-path

Question

I have test code that wants to require some utility code in the same directory. I would prefer to not update the load-path, as most of the time, I do not want me or any other user who has checked out this code to be looking in this directory.

It seemed that (require 'utils "./utils.el") should work, but this gives me an error:

file-remote-p: Cannot open load file: No such file or directory, ./utils.el

Is there a better way than something like

(let ((load-path (append (list (file-name-directory (buffer-file-name))))
                         load-path)))
    (require 'utils))

I also cannot specify an absolute path, as the path may be different when other users check out the repository.

Have you tried `expand-file-name`? – npostavs Apr 26 '17 at 19:49 — npostavs, Apr 26 '17 at 19:49
You could also try load-file instead. – John Kitchin Apr 26 '17 at 23:04 — John Kitchin, Apr 26 '17 at 23:04

Heikki · Accepted Answer · 2019-02-23T09:03:49.507

11

Like John Kitchin pointed out, load-file does what you want. For example:

(setq my-utils-file "utils.el")
(load-file 
  (expand-file-name my-utils-file
                    (file-name-directory (buffer-file-name))))

edited Feb 23 '19 at 09:03

answered Apr 27 '17 at 05:43

Heikki

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Require a file in the current directory without setting load-path

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