Count the number of 0 and 1 in a file

Question

I have a file (see below), and I would like to count the number of 1's and of 0's:

1
1
1
0
0
1
1
0
0
0
...

I tried to use awk but it doesn't work, for example, to count the number of 1's:

awk -F "1\n" '{print NF-1}'

How shall I do it?

I assume the file only contains 1's and 0's, and each line is just a single number. But I more like to know how to generalize to the case for counting the occurrences of a specific line in a file.

Answer 1

This counts the number of ones and zeros in filename:

$ sort <filename | uniq -c
      5 0
      5 1

Answer 2

With awk:

awk '/0/{zero++} /1/{one++} END{printf "0: %d\n1: %d\n", zero, one}' filename

With grep, needing two commands:

grep -c 1 filename
grep -c 0 filename

---

For a string that covers the entire line:

grep -cFx 'target string' filename

Presumably your string might contain characters that have special meaning in regex, so we need to use -F. -x specifies that the whole line must match.

With awk:

awk '$0 == "target string" {count++} END {print count}'

Answer 3

Delete everything but 0 and print the character counts:

tr -cd 0 < file | wc -m

Output:

5

Answer 4

Another possibility is to grep for lines matching exact "0" (or "1") and count the resulting lines:

grep "^0$" filename | wc -l

=> 5

grep "^1$" filename | wc -l

=> 5

Or count both alternatives in a single grep:

grep "^[01]$" filename | wc -l

=> 10

Answer 5

Ed, man! !man ed:

$ ed -s file <<EOT
g/0/d
n
u
g/1/d
n
EOT

13  1
17  0

Answer 6

perl -n0E 'say tr/0//, "+",tr/1//'

or following OP tentative:

awk -v RS=1 'END{print NR-1}'