7

Here's a subset of the file names in my file:

profile_10_1_1
profile_10_1_2
profile_1_1_1

I'm trying to sort them numerically in ascending order, that is starting from 1 onwards. I used the following command 

sort -n filename

and also tried this:

sort -nk filename

But the ones with 10 will always be at the top of the list.

How do I write a command to get this desired output:

profile_1_1_1
profile_1_1_2
....
profile_9_1_1
....
profile_10_1_1
terdon
  • 242,166
cwmwl
  • 73

2 Answers2

7

FreeBSD and GNU sort have a -V option for that.

sort -V < filename

GNU ls has a -v option. So if those files do exist, you could do:

xargs -d '\n' < filename ls -dv --

zsh has parameter expansion flags to sort arrays numerically:

printf '%s\n' ${(fno)"$(<filename)"}

Otherwise, portably, you'd have to do it like:

sort -t_ -k1,1 -k2,2n -k3,3n -k4,4n -k5,5n filename
Stéphane Chazelas
  • 544,893
3

-V does exactly what you want.

-V, --version-sort
              natural sort of (version) numbers within text

Works at least in GNU sort.

jimmij
  • 47,140