Why do brackets in a grep pattern remove the grep process from ps results?
$ ps -ef | grep XXXX
[...] XXXX
[...] grep XXXX
$ ps -ef | grep [X]XXX
[...] XXXX
Why do brackets in a grep pattern remove the grep process from ps results?
$ ps -ef | grep XXXX
[...] XXXX
[...] grep XXXX
$ ps -ef | grep [X]XXX
[...] XXXX
When you run ps -ef | grep string, grep is displayed in the output because string matches [...] grep string.
But, when you run ps -ef | grep [s]tring the line isn't displayed, because grep translates [s]tring to string, while ps outputs [...] grep [s]tring, and that doesn't match string
[] represents any one of the set of characters within the brackets of which, in this case "s" is the only one...
– Dennis Williamson
Sep 16 '10 at 01:53
Because the brackets need to be escaped, for bash once and for grep again:
$ ps -ef | grep \\[X\\]XXX
[...] XXXX
[...] grep XXXX
$ ps -ef | grep "\[X\]XXX"
[...] XXXX
[...] grep XXXX