Get number of files in each directory

Question

I have a directory with a very large number of subdirectories (~800) that were generated programmatically. I want to get a count of the number of files in each of these subdirectories to check for anomalies (if the code broke on a run then some of the files will be missing). What's a quick way to do this? The sort of output I'm looking for is:

Name_of_Folder_1 [# of files in Folder 1]   
Name_of_Folder_2 [# of files in Folder 2]
...

It's rarely used, but diff will happily report the differences between folders. diff folder1 folder2. — steve, Aug 12 '15 at 20:30
See also How can I get a count of files in a directory using the command line? and there are more related questions if you take the time to search the site. — don_crissti, Aug 12 '15 at 20:41

Matt · Answer 1 · 2015-08-12T22:25:07.497

2

This will get you the count of files in each subdirectory of the current directory, dealing with any strange file names (with gnu find).

find . -maxdepth 2 -mindepth 2 -type f -printf "%h\0" | uniq -zc | tr '\0' '\n'

edited Aug 12 '15 at 22:25

answered Aug 12 '15 at 20:48

Matt

8,991

score 1 · Accepted Answer · answered Aug 12 '15 at 20:21

1

Assuming that you have no spaces in your directory names:

for dir in $(find . -type d); do
    echo "${dir}: $(find ${dir} -maxdepth 1 -type f | wc -l)"
done

answered Aug 12 '15 at 20:21

Andy Dalton

13,993

1

see also: Get recursive file count – Evgeny Aug 12 '15 at 20:30
How to process files with spaces? – Systems Rebooter May 31 '20 at 07:43

Get number of files in each directory

2 Answers2