What can you do with the eval
command? Why is it useful? Is it some kind of a built-in function in bash? There is no man
page for it..

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11 Answers
eval
is part of POSIX. It's an interface which can be a shell built-in.
It's described in the "POSIX Programmer's Manual": http://www.unix.com/man-page/posix/1posix/eval/
eval - construct command by concatenating arguments
It will take an argument and construct a command of it, which will then be executed by the shell. This is the example from the manpage:
foo=10 x=foo # 1
y='$'$x # 2
echo $y # 3
$foo
eval y='$'$x # 5
echo $y # 6
10
- In the first line you define
$foo
with the value'10'
and$x
with the value'foo'
. - Now define
$y
, which consists of the string'$foo'
. The dollar sign must be escaped with'$'
. - To check the result,
echo $y
. - The result of 1)-3) will be the string
'$foo'
- Now we repeat the assignment with
eval
. It will first evaluate$x
to the string'foo'
. Now we have the statementy=$foo
which will get evaluated toy=10
. - The result of
echo $y
is now the value'10'
.
This is a common function in many languages, e.g. Perl and JavaScript. Have a look at perldoc eval for more examples: http://perldoc.perl.org/functions/eval.html

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8In shell terminology,
eval
is a built-in, not a function. In practice, built-ins behave a lot like functions that don't have an in-language definition, but not quite (as becomes apparent if you are twisted enough to define a function calledeval
). – Gilles 'SO- stop being evil' Oct 23 '11 at 01:17 -
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9
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14Backticks are shorthand for executing another entire shell, meaning you'll have another child bash/sh process running within your script. – Aaron R. Oct 19 '15 at 15:38
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1Why echo $y (stage 3) brings back foo(10) instead of $foo ? (i.e just the value of foo instead of the string $ + the value of foo) ? – Dec 25 '16 at 17:00
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1@Benia Because
$y
is defined right above it as a literal$
followed by the value of$x
which exands tofoo
. – Ken Sharp Jan 30 '17 at 13:06
Yes, eval
is a bash internal command so it is described in bash
man page.
eval [arg ...]
The args are read and concatenated together into a single com-
mand. This command is then read and executed by the shell, and
its exit status is returned as the value of eval. If there are
no args, or only null arguments, eval returns 0.
Usually it is used in combination with a Command Substitution. Without an explicit eval
, the shell tries to execute the result of a command substitution, not to evaluate it.
Say that you want to code an equivalent of VAR=value; echo $VAR
. Note the difference in how the shell handles the writings of echo VAR=value
:
1.
andcoz@...:~> $( echo VAR=value )
bash: VAR=value: command not found
andcoz@...:~> echo $VAR
<empty line>
The subshell executes the echo
command and then command substitutes the result, VAR=value
, back to the outer shell where it throws the error because "VAR=value" is not a command. The assignment remains ineffective because it was never executed, only echo
ed.
2.
andcoz@...:~> eval $( echo VAR=value )
andcoz@...:~> echo $VAR
value
The subshell echo
es "VAR=value" which is again command substituted back to the outer shell where it is then eval
ed.
Last but not least, eval
can be a very dangerous command. Any input to an eval
command must be carefully checked to avoid security problems.
-
-
Perhaps when you say
Without an explicit eval, the shell tries to execute the result of a command substitution, not to evaluate it.
In your answer you should explain what the difference is between those two with a definition before going to a lengthy example? Ok, will try to go through it to write such an answer. – Charlie Parker Jun 07 '22 at 21:48 -
this seems like a good answer. Will go through it. Another common example I've seen is
eval $(opam env)
e.g. here: https://stackoverflow.com/questions/72522412/what-does-eval-opam-env-do-does-it-activate-a-opam-environment/72537901#72537901 – Charlie Parker Jun 08 '22 at 14:24 -
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1what confuses me is that
$(echo Var=value)
that$(...)
does is "allows a command to be run and its output to be pasted back on the command line as arguments to another command." So to me the output of$(...)
should have been given to the terminal as I typed it to the terminal i.e.Var=val
which does let me run it. Instead I don't know to what function it's been given that interprets the output of$(...)
as commands to be ran. Very confusing to me. tldr: what is the function receiving the output of $(...) and what is the string output of $(...)? – Charlie Parker Jun 08 '22 at 15:05
The eval statement tells the shell to take eval’s arguments as command and run them through the command-line. It is useful in a situation like below:
In your script if you are defining a command into a variable and later on you want to use that command then you should use eval:
/home/user1 > a="ls | more"
/home/user1 > $a
bash: command not found: ls | more
/home/user1 > # Above command didn't work as ls tried to list file with name pipe (|) and more. But these files are not there
/home/user1 > eval $a
file.txt
mailids
remote_cmd.sh
sample.txt
tmp
/home/user1 >

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14The comment in line 4 of your example is wrong: It should be "Above command didn't work because bash tried to find a command called
ls | more
. In other words: The single command name consisted of nine characters, including the spaces and the pipe symbol. – cfi Oct 16 '15 at 13:41 -
1I get exactly the same behavior he reported. bash --version == GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin18) – Alexander Bird Apr 26 '19 at 17:24
What is eval?
eval is a shell command which is usually implemented as a builtin.
In POSIX it is listed as part of "2.14. Special Built-In Utilities" at the entry "eval".
What builtin means is:
The term "built-in" implies that the shell can execute the utility directly and does not need to search for it.
What does it do?
In simple terms: makes an input line to be parsed twice.
How does it do that?
The shell has a sequence of steps that it follows to "process" a line. You could look at this image and realize that eval is the only line that goes up, back to step 1, on the left. From the POSIX description:
2.1 Shell Introduction
- The shell reads its input ....
- The shell breaks the input into tokens: words and operators
- The shell parses the input into simple and compound commands.
- The shell performs various expansions (separately) ...
- The shell performs redirection and removes redirection operators and their operands from the parameter list.
- The shell executes a function, built-in, executable file, or script ...
- The shell optionally waits for the command to complete and collects the exit status.
At step 6 a built-in will be executed.
At step 6 eval causes the processed line to be sent back to step 1.
It is the only condition under which the execution sequence goes back.
That is why I say: With eval an input line is parsed twice.
Effects of parsing twice.
The first.
And most important effect to understand. Is that one consequence of the first time a line is subject to the seven shell steps shown above, is quoting. Inside step 4 (expansions), there is also a sequence of steps to perform all expansions, the last of which is Quote Removal:
Quote removal shall always be performed last.
So, always, there is one level of quoting removed.
Second.
As consequence of that first effect, additional/different parts of the line become exposed to the shell parsing and all the other steps.
Example.
Indirection.
That allows to execute indirect expansions:
a=b b=c ; eval echo \$$a ### shall produce "c"
Why?
Because on the first loop, the first $
is quoted.
As such, it is ignored for expansions by the shell.
The next $
with the name a is expanded to produce "b".
Then, one level of quoting is removed, making the first $
unquoted.
End of first loop.
It is then, on the second loop that the string $b
is read by the shell.
Then expanded to "c"
And given as an argument to echo
.
To "see" what eval will produce on the first loop (to be evaluated again), use echo. Or any command/script/program that clearly shows the arguments:
$ a=b b=c
$ eval echo \$$a;
c
Replace eval by echo to "see" what is happening:
$ echo echo \$$a
echo $b
It is also possible to show all the "parts" of a line with:
$ printf '<%s> ' echo \$$a
<echo> <$b>
Which, in this example, is only one echo and one variable, but remember it to help in evaluating more complex cases.
A correction.
It must be said that: there is a mistake in the code above, can you see it?.
Easy: there are some quotes missing.
How? you may ask. Simple, let's change the variables (not the code):
$ a=b b="hi jk"
$ eval echo \$$a
hi jk
See the missing spaces?
That is because the value inside $b
was split by the shell.
If that does not convince you, try this:
$ a=b b="hi * jk"
$ eval echo \$$a ### warning this will expand to the list
### of all files in the present directory.
Why?
Missing quotes. To make it work correctly (add internal "$a"
and external \"
quotes).
Try this (is perfectly safe):
$ a=b b="hi * jk"
$ eval echo \" \$"$a" \"
hi * jk
About the manual:
There is no man page for it..
No, there is not an independent man page for this.
The search for manual with man -f eval
or even apropos eval
show no entry.
It is included inside man bash
. As is any built-in.
Search for "SHELL BUILTIN COMMANDS" and then for "eval".
An easier way to get help is:
In bash, you could do help eval
to see the help for the built-in.
Why is eval called evil?
Because it is binding text to code dynamically.
In other words: it converts the list of its arguments (and/or expansions of such arguments) into an executed line. If for any reason, an argument has been set by an attacker, you will be executing attacker code.
Or even simpler, with eval you are telling whoever defined the value of one or several arguments:
C'mon, sit here and type any command line, I will execute it with my powers.
Is that dangerous? Should be clear for everyone that it is.
The safety rule for eval should be:
Only execute eval on variables to which you have given it's value.
Read more detail here.
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Thank you for the detailed explanation. I have a question on the term you used: "quoted". On the first example I see the
$
being escaped, not quoted. Is escaped characters the same as quoted with single quotes (except for the few escapes allowed inside single quoted text)? Does the documentation refer to escaped text as quoted text? If that's the case I'll want to re-read it to make things clearer in my head. – Spidey May 21 '21 at 21:36 -
This link is broken:
You could [look at this image](http://helios.cs.ifmo.ru/~ad/Documentation/Bash_Shell/bash3-CHP-7-SECT-3.html) and realize...
– Seamus Feb 04 '22 at 17:56 -
V. good & thorough answer, but: I found this answer trying to understand this one-liner:
eval "$(ssh-agent -s)"
. As I understand it,ssh-agent
must be running in the background to supportssh-add
& other key ops. Unfortunately, I still don't understand this :/ – Seamus Feb 04 '22 at 18:05
eval
has no man page because it is not a separate external command, but rather a shell built-in, meaning a command internal to and known only by the shell (bash
). The relevant part of the bash
man page says:
eval [arg ...]
The args are read and concatenated together into a single command.
This command is then read and executed by the shell, and its exit
status is returned as the value of eval. If there are no args, or only
null arguments, eval returns 0
In addition, the output if help eval
is:
eval: eval [arg ...]
Execute arguments as a shell command.
Combine ARGs into a single string, use the result as input to the shell,
and execute the resulting commands.
Exit Status:
Returns exit status of command or success if command is null.
eval
is a powerful command and if you intend to use it you should be very careful to head off the possible security risks that come with it.

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eval
is a feature of most interpreted languages (TCL
, python
, ruby
...), not only shells. It's used to evaluate code dynamically.
In shells, it's implemented as a shell builtin command.
Basically, eval
takes a string as argument and evaluates/interprets the code in it. In shells, eval
can take more than one argument, but eval
just concatenates those to form the string to evaluate.
It's very powerful because you can construct code dynamically and run it, something you can't do in compiled languages like C.
Like:
varname=$1 varvalue=$2
eval "$varname=\$varvalue" # evaluate a string like "foo=$varvalue"
# which in Bourne-like shell language
# is a variable assignment.
But it's also dangerous as it's important to sanitize the dynamic (externally provided) parts of what is passed to eval
for the very reason it's interpreted as shell code.
For instance, above if $1
is evil-command; var
, eval
would end-up evaluating the evil-command; var=$varvalue
shell code and then run that evil-command
.
The evilness of eval
is often over-exaggerated.
OK, it's dangerous, but at least we know it's dangerous.
A lot of other commands will evaluate shell code in its arguments if not sanitized, like (depending on the shell), [
aka test
, export
, printf
, GNU sed
, awk
, and of course sh
/bash
/perl
and all interpreters...
Examples (here using uname
as the evil-command
and $a
as externally provided unsanitized data):
$ a='$(uname>&2)' sh -c 'eval "echo $a"'
Linux
$ a='x[0$(uname>&2)]' mksh -c 'export "$a=$b"'
Linux
$ a='x[0$(uname>&2)]' ksh93 -c 'printf "%d\n" "$a"'
Linux
0
$ a='x[0$(uname>&2)]' ksh93 -c '[ "$a" -gt 0 ]'
Linux
$ a=$'bar/g;e uname>&2\n;s//'; echo foo | sed "s/foo/$a/g"
Linux
bar
$ a='";system("uname");"'; awk "BEGIN{print \"$a\"}"
Linux
$ a=';uname'; sh -c "echo $a"
Linux
Those sed
, export
... commands could be considered more dangerous because while it's obvious eval "$var"
will cause the content of $var
to be evaluated as shell code, it's not so obvious with sed "s/foo/$var/"
or export "$var=value"
or [ "$var" -gt 0 ]
. The dangerosity is the same, but it's concealed in those other commands.

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@BinaryZebra,
sed
likeeval
is being passed a string contained in a variable, and for both, the content of that string ends up being evaluated as shell code, sosed
is as dangerous aseval
, that's what I'm saying.sed
is being passed a string containinguname
(uname has not been executed so far) and through the invocation ofsed
, the uname command ends up being executed. Like for eval. Insed 's/foo/$a/g'
, you're not passing unsanitized data tosed
, that's not what we're talking about here. – Stéphane Chazelas Dec 19 '15 at 20:52 -
Great answer, really clarifies it for me. We can use
eval
to dynamically assign both values and variable names! – information_interchange Aug 10 '20 at 18:57
This example may shed some light:
#!/bin/bash
VAR1=25
VAR2='$VAR1'
VAR3='$VAR2'
echo "$VAR3"
eval echo "$VAR3"
eval eval echo "$VAR3"
Output of the script above:
$VAR2
$VAR1
25

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Thanks for your contribution, but, as entertaining as they are, we aren’t really interested in compiling a list of (slightly different) examples of using
eval
. Do you believe that there is some fundamental, critical aspect of the functionality ofeval
that isn’t covered in the existing answers? If so, then explain it, and use the example to illustrate your explanation. Please do not respond in comments; [edit] your answer to make it clearer and more complete. – Scott - Слава Україні Sep 14 '18 at 16:43 -
This example may be confusing because not everyone understands the difference between single and double quotes in bash. Put all those variables in double quotes and it will bring a different result. – t7e Jun 21 '22 at 22:29
My experience with eval
it can convert string output of command to variable , this example from another question
eval $(ffprobe -v error -of flat=s=_ -select_streams v:0 -show_entries stream=height,width ${FILE})
when I type it directly to the terminal, I got
streams_stream_0_width=1280
streams_stream_0_height=720
That stored each one into a new variable to use it inside the script.
IN_WIDTH=${streams_stream_0_width}
This could be useful to benefit, from another command output, before processing the main command (e.g get file properties or remote server status )

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A bit late to the party on this but this little example from my console output shows the behaviour of eval versus running a script. It shows that eval evaluates a string (be it from a file or variable) and runs the command in the current shell it's in, compared to running a script, which runs in its own shell and exits back to the current shell. (but also to run a script in the current shell environment, you can just place a dot and a space before the shell script filename)
$ pwd
/home/user1
$ cat myscript.sh
cd Desktop
$ ./myscript.sh
$ pwd
/home/user1
$ eval $(cat myscript.sh)
$ pwd
/home/user1/Desktop

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1You probably need to quote the expansion of the command substitution. Test it with a directory that has space in its name (the script would do
cd "My dir"
). – Kusalananda Jun 14 '21 at 12:20
The eval
function/macro evaluates Shell code represented as a string and returns its completion value.
The source is parsed as a bash shell.

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Simply put, eval
takes all the arguments provided to it, combines them into a single command, and then executes that command.
command_part1="ls"
command_part2="-l"
eval "$command_part1 $command_part2"
is the same as
ls -l

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type command
to learn of what type a command is. (type eval
in ths case) – rozcietrzewiacz Oct 22 '11 at 20:38help eval
to get "man" page from your shell – m-ric Nov 28 '16 at 19:36help eval zsh: command not found: help
doesn't work? – Charlie Parker Jun 07 '22 at 21:46eval $(opam env)
. – Charlie Parker Jun 07 '22 at 21:47