3

I created 512 files, with names made from combinations of permisions (r, w, x).

I created them like this:

touch ./{r,-}{w,-}{x,-}{r,-}{w,-}{x,-}{r,-}{w,-}{x,-}

and I want the files to have same permisions as their name indicates, for example, files r-x--xrwx should have permissions r-x--xrwx.

I tried to do it like this:

for i in *
do
    u=${i:0:3};g=${i:3:3};o=${i:6:3}
    chmod u=$u,g=$g,o=$o -- $i
done

Some of the files end up with the correct permissions, but, for others, permissions don't match the name. How can I fix this?

dhag
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user3706129
  • 31

2 Answers2

5

The parameters you're passing to chmod include - symbols but shouldn't. To fix that, remove the - symbols:

for i in *
do
  u=${i:0:3};g=${i:3:3};o=${i:6:3};
  u=${u//-/};g=${g//-/};o=${o//-/};
  chmod -- "u=$u,g=$g,o=$o" "$i"
done
Stéphane Chazelas
  • 544,893
Stephen Kitt
  • 434,908
0

You may convert the names into an octal number (e.g. 744) and use it to change permissions:

#!/bin/bash
# touch ./{r,-}{w,-}{x,-}{r,-}{w,-}{x,-}{r,-}{w,-}{x,-}

for filename in *
do
    str="$filename"
    str="${str//-/0}"
    str="${str//[^0]/1}"
    dec="$((2#$str+0))"
    oct="$(printf '%03o' "$dec")"
    #echo "$str $dec $oct : "
    chmod -- "$oct" "$filename"
done

The octal number is obtained by:

  • change each - to a zero 0, each any other letter by a one 1.
  • convert the binary number to a decimal (because the shell understand only decimal).
  • convert the decimal number into octal.
  • use the octal number to change permissions.

The -- in the chmod command is because filenames with several dash - are confusing to the command, it believes that the filename is an option.