Print content between brackets in different lines

Question

How to print the content between two brackets.

For example:

return [ "server1.domain.com" ,

"server2.domain.com" ,

"server3.domain.com" ]

Expected result:

   "server1.domain.com" ,

   "server2.domain.com" ,

   "server3.domain.com"

How to get the expected result?

score 4 · Accepted Answer · answered Sep 14 '16 at 12:48

4

With pcregrep:

pcregrep -Mo 'return \[\K[^]]*'

Multiline match on return [ followed by a sequence of non-] characters but only output the part to Keep (to the right of \K).

answered Sep 14 '16 at 12:48

Stéphane Chazelas

544,893

Thank you for the reply.. Is it possible to do this with grep command. – manth Sep 14 '16 at 12:52
2

@manth, pcregrep is one of many grep implementations. Some other grep implementations like some versions of GNU grep will also work there if you replace the pcregrep -Mo with grep -zPo and pipe the output to tr '\0' '\n' – Stéphane Chazelas Sep 14 '16 at 12:56

score 1 · Answer 2 · answered Sep 14 '16 at 14:01

With sed

sed '
    /.*\[ /{
        s///        #remove all upto open square bracket 
        :a          #return mark
        /\ ].*/!{
            N       #get next line untill there is close square bracket
            ba      #back to return mark
        }
        s///        #remove all from close square bracket to end of line 
     }
     '

Print content between brackets in different lines

2 Answers2

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