How to create a list file of some files?

Question

i have a bunch of files from log1 to log164, how can i create a file like below ordering... please help me...

log1.gz
log10.gz
log100.gz
log101.gz
log102.gz
log103.gz
log104.gz
log105.gz
log106.gz ...etc

i need like these... log1.gz log10.gz log100.gz log101.gz log102.gz log103.gz log104.gz log105.gz log106.gz ...etc — Prasannakumar Merugu, Nov 01 '16 at 06:30
What do you need? A enumerated ordered list (a list with row number, a file name per row and rows are separated by new line) or an ordered list where each file name is separated by space! — trishnendu, Nov 01 '16 at 06:44

score 1 · Answer 1 · answered Nov 01 '16 at 07:20

You can get an ordered list by simply using ls -v. But the next formatting part is a bit trickier. If you need an enumerated list (I am assuming the formating is same as in your question) you can use awk. Use pipe to feed the ls -v output to awk.

ls -v | awk '{print NR ".",$0}'

If you don't need the enumeration, then it can be done without awk. In the output of ls -v replace the spaces by a new line character.

ls -v | tr ' ' '\n'

How to create a list file of some files?

1 Answers1