3

I'm trying to write a very simple mkcd command:

#!/bin/bash
mkdir $1
cd $1

The directory is created but the change directory part doesn't seem to run.

Update based on comment:

mkcd () {
  mkdir "$1"
  cd "$1"
}

I'm trying to run it first as a local file:

./mkcd

My end location is /opt/bin, neither location seems to work.

techraf
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Philip Kirkbride
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1 Answers1

8

It needs to be a function:

mkcd() { mkdir -p "$1" && cd "$1"; }

A script will get run inside its own separate process. Changing directories there will have no effect on the parent shell (neither will changing directories inside a subshell as in (cd /tmp)).

Petr Skocik
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  • With that it doesn't seem to make the folder. I will double check that I did it exact. – Philip Kirkbride Dec 08 '16 at 13:39
  • It's a function so you'd place it inside your .bashrc or an insourcable text file placed in a $PATH directory. You'd then include the textfile with . the_textfile.sh (assuming it's named the_textfile.sh -- the_textfile.sh need not and should not be marked executable with chmod). Since this file is insourced with . (or source) (implicitly done for bash startup files such as .bashrc) and not executed, a shebang line makes no sense there (it will be interpreted as just a comment). – Petr Skocik Dec 08 '16 at 13:40
  • I have always put these types in /opt/bin with chmod +x (should that work?). The function is found when I run mkcd but nothing happens. It must be another issue with my system because I also tried copying from here. http://unix.stackexchange.com/questions/9123/is-there-a-one-liner-that-allows-me-to-create-a-directory-and-move-into-it-at-th – Philip Kirkbride Dec 08 '16 at 13:47
  • @PhilipKirkbride Make it a mkcd.sh, have it in your /opt/bin, don't chmod +x it, and in your .bashrc add . mkcd.sh. Or just put mkcd(){ mkdir -p "$1" && cd "$1"; } inside your .bashrc and don't bother with the insourcable. – Petr Skocik Dec 08 '16 at 13:50
  • when I try that I get mkcd not found. I can use mkcd.sh globally but because I did chmod -x, permission is denied. Will try .bashrc method. – Philip Kirkbride Dec 08 '16 at 13:53
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    I think problem was I didn't close the terminal to refresh my .bashrc – Philip Kirkbride Dec 08 '16 at 13:55
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    My version: mkcd() { if [ ! -e "$@" ];then mkdir -p "$@" && cd "$@";fi; }. – neverMind9 Jun 20 '19 at 20:20
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    @neverMind9 I kind of assume it was for interactive use and therefore time wasn't of the essence. [ -d "$1" ] || mkdir -p "$1" is good for saving time on process start overheads in scripts, though. (I think -d is better than -e because then you'll run mkdir iff the arg isn't a directory and mkdir will then generate an error message for you). – Petr Skocik Jun 20 '19 at 20:25
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    @PSkocik Sorry for the mistake in the last one. I updated it (and moved the “cd” part outside of the “if” request): mkcd() { if [ ! -d "$@" ];then mkdir -p "$@" ;fi; cd "$@"; }. – neverMind9 Jun 20 '19 at 20:28