"merge" the contents of one shell script file into another

Question

Having a "library" with constants and functions (lib.sh), I can include it in my script (script.sh)

. /myfolder/lib.sh
......

Is there a way to merge the included file in the script (i.e. replace ./myfolder/lib.sh with the content of lib.sh)?

Why are you talking about bash in your title if the content refers to ksh? — Chris Davies, Jan 09 '17 at 14:31
see http://unix.stackexchange.com/questions/141387/sed-replace-string-with-file-contents — ctrl-alt-delor, Jan 09 '17 at 14:43
@IporSircer >> would put it at the end, where it is too late. — ctrl-alt-delor, Jan 09 '17 at 14:44
do you want something specific to this case? (process script.sh and replace ". /myfolder/lib.sh" with the contents of lib.sh), or a more general solution that replaces any . or source command with the corresponding contents? — Jeff Schaller, Jan 09 '17 at 14:51
I would go for a general case, where the source might include another source. Something like "compilation" of everything into one file. — Ciprian Constantinescu, Jan 10 '17 at 13:51

xhienne · Answer 1 · 2017-01-09T16:55:58.197

1

Use sed:

sed -i.bak '\|^\. /myfolder/lib\.sh| {
    r /myfolder/lib.sh
    d
}' script.sh

What this script does is:

\|^\. /myfolder/lib\.sh| { ... } => locate lines that begin with . /myfolder/lib.sh and execute the commands inside the braces
r /myfolder/lib.sh => output the content of /myfolder/lib.sh
d => delete the line (. /myfolder/lib.sh)

The other lines are left as is of course.

edited Jan 09 '17 at 16:55

answered Jan 09 '17 at 16:44

xhienne

score 0 · Answer 2 · answered Jan 09 '17 at 14:50

0

untested: use GNU awk

gawk -i inplace '
    $1 == "." {system("cat " $2); next}
    {print}
' script.sh

answered Jan 09 '17 at 14:50

glenn jackman

2 Answers2