Consider path in a directory structure
/A/B/C/D
/A/B/C/E
/A/B/O/P
now if I want to list all path which has sub directory C in it, then can it be done through grep? Expected output:
/A/B/C/D
/A/B/C/E
I tried using grep and find but could not achieve this.
While ka3ak's answer works, find comes with a parameter "-path" so you can simply use
find . -type d -path "*/c/*"
-path seems also a bit faster:
[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e
real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e
real 0m0,012s
user 0m0,007s
sys 0m0,003s
You only need find for this:
find A -type d -regextype posix-extended -regex ".*/C/.*"
For the following directory structure
A
└── B
├── C
│ ├── D
│ └── E
├── C1
│ └── E
└── O
└── P
it would return:
A/B/C/E
A/B/C/D
