In this answer, what is the use of -! in find?
Consider the following code:
find . -type l -! -exec test -e {} \; -print
This alternative seems to do the same exact thing:
find . -type l ! -exec test -e {} \; -print
It appears the -! works like !, meaning negation of the following expression. Which makes sense. But why not just ! then? I can't seem to find any documentation on such syntax.
find). – Michael Homer Mar 08 '17 at 05:22findin NetBSD – Fox Mar 08 '17 at 13:40