Find all files and use the result in grep search pattern

Question

I found an example which uses a combination of find and xarg or exec to search a specific pattern from the result see link here.
However I'd like to use the result of find command and use it as search pattern for grep. Something like command below but am not sure how to construct it.

find . -name "*.cgi" -printf '%f\n' | cut -d. -f1 | xarg grep 'find_result' *.html

@SatoKatsura thanks but it doesn't work... – dimas May 24 '17 at 14:14 — dimas, May 24 '17 at 14:14

Satō Katsura · Accepted Answer · 2017-05-24T14:19:57.423

3

Assuming GNU grep, and assuming your filenames don't have embedded newlines:

find . -name '*.cgi' -printf '%f\n' | cut -d. -f1 | sort -u | fgrep -f - *.html

edited May 24 '17 at 14:19

answered May 24 '17 at 14:14

Satō Katsura

13,368
2
31
50

Eric Renouf · Answer 2 · 2017-05-24T14:25:20.843

2

You don't need xargs here, you can just have grep read the pattern list from stdin:

with GNU find:

find . -name '*cgi' -printf '%f\n' | grep -f - *html

otherwise:

find . -name '*cgi' | cut -f2- -d/ | grep -f - *html

edited May 24 '17 at 14:25

answered May 24 '17 at 14:14

Eric Renouf

18,431

thanks Eric... this one works as well but I have to give the points to sato – dimas May 24 '17 at 14:16

Find all files and use the result in grep search pattern

2 Answers2