Call function that call ffmpeg in loop

Question

I have function like this (got it form some website long ago):

function flv2mp3() {
    ffmpeg -y -i "$1" -acodec libmp3lame "$(echo -n "$1" | sed -e 's/\.[^\.]*$//').mp3"
}

and I'm trying to call that function in loop:

find . -name 'Rage*' -not -name '*.mp3' -print0 | \
while read -d '' -r file; do
   flv2mp3 "$file";
done

but got wierd result, it seems that it's after first invocation I 've got something like this:

stream #1:
  keyframe=1
  duration=0.023
  dts=94.923  pts=94.923
  size=388
stream #1:
  keyframe=1
  duration=0.023
  dts=94.946  pts=94.946
  size=381

Enter command: <target>|all <time>|-1 <command>[ <argument>]

and it waiting for input, what's going on? I can call flv2mp3 function without the loop just fine and it covert video to mp3.

I've also tried to put this:

flv2mp3 "$(echo -n $file | sed 's%./%%')"

because the files have ./ at the beginning but got the same results.