I have this code:
for i in 'some text' "some other text"
do
echo $i
done
The output is:
some text
some other text
Why the spaces are not being printed?
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Cyrus
- 12,309
user267935
- 365
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1Please Read Security implications of forgetting to quote a variable in bash/POSIX shells – Dec 29 '17 at 01:56
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I don't think the down votes are all that appropriate, it is a well formatted and to the point question from a new user. – jesse_b Dec 29 '17 at 02:11
2 Answers
0
Because it expands to
echo some text
which will result in the output you gave. That is why we should quote our variables in most cases. Try to replace echo $i with echo "$i" and see the difference.
Weijun Zhou
- 3,368
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I had thought that the command executed is still
echo some(many spaces here)textbut the spaces are trimmed when that command is executed. Did I miss something, or the concept that has been in my mind for long wrong? – Weijun Zhou Dec 29 '17 at 01:59 -
1If this is the case, thank you very much for correcting my long-held belief. I will edit the answer. – Weijun Zhou Dec 29 '17 at 02:01
0
Quote your expansions echo "$i":
$ for i in 'some text' "some other text"
do
echo "$i"
done
Prints
some text
some other text
Please read.