modifying the zsh shell word split

Question

I am using the word split style shell (select-word-style shell). I like it in general but would like to split at forward slashes also, so that when I go forward/backward a word, if the word doesn't contain any /s, it completely skips over the word but if it does contain one or more slashes, it stops at the first slash.

Any ideas?

score 36 · Answer 1 · answered Sep 19 '12 at 09:15

36

man zshall /forward-word /backward-word

echo $WORDCHARS
*?_-.[]~=/&;!#$%^(){}<>
WORDCHARS='*?_-.[]~=&;!#$%^(){}<>'  ;# without /

answered Sep 19 '12 at 09:15

Nahuel Fouilleul

1,584

7

+1 I wonder why this is not the default. Paths are probably the single most used entity in a command line. – Mischa Arefiev Sep 19 '12 at 10:51
1

A more succinct version is WORDCHARS=${WORDCHARS//[\/]}. – James O'Gorman Sep 19 '12 at 14:24
5

even shorter WORDCHARS=${WORDCHARS/\/} – Nahuel Fouilleul Sep 19 '12 at 14:44
2

or WORDCHARS=$WORDCHARS:s:/: – Stéphane Chazelas Nov 17 '12 at 21:39
is it only me or ; isn't needed ? I would add '"' and "'" (single and double quotes) and ~ – elig Mar 29 '20 at 07:51
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This works in the default configuration, but the question assumes select-word-style shell, and that ignores $WORDCHARS. – Gilles 'SO- stop being evil' Aug 20 '21 at 21:28
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I personally use WORDCHARS='_' – Samuel Coskey May 10 '22 at 21:32
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@SamuelCoskey indeed this is more consistent with others character classes like regex word characters \w – Nahuel Fouilleul May 11 '22 at 09:37

modifying the zsh shell word split

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