how do you compare two folders and copy the difference to a third folder using a shell script

Question

#!/bin/sh
# This is comment!
echo Hello World
for file1 in /C:/Users/shubham.tomar/Desktop/Shell/Test1/*; 
do
filename1=$(basename "$file1")
echo $filename1
echo "------------------------"
for file2 in /C:/Users/shubham.tomar/Desktop/Shell/Test2/*;
do
filename2=$(basename "$file2")
echo $filename2
if [["filename1" = "filename2"]]; then
echo "---File matched---"
else
mv -f /C:/Users/shubham.tomar/Desktop/Shell/Test2/$filename2 /C:/Users/shubham.tomar/Desktop/Shell/Moved/
fi
echo "--------------File Moved-----------"
done
done

**

NOTE ABOUT PROBLEM

**

There are some files in a particular path for ex: Desktop/Test1 and Downloads/Test2 I want to write a shell script to move all the files present in Test2 and not in Test1 to a path for ex: Documents/MovedFiles files may be of any type

Answer 1

Using nested for loops is wrong. You don't want to compare every file name from Test1 with every file name in Test2.

Edit: Some additionall script lines for debugging and to avoid using file *.

#!/bin/sh

# Check if this is correct
dir1="/C:/Users/shubham.tomar/Desktop/Shell/Test1"
# maybe you have to write
# dir1="/c/Users/shubham.tomar/Desktop/Shell/Test1"
dir2="/C:/Users/shubham.tomar/Desktop/Shell/Test2"
targetdir="/C:/Users/shubham.tomar/Desktop/Shell/Moved"

# for debugging
echo contents of dir1 $dir1
ls "$dir1"
echo contents of dir2 $dir2
ls "$dir2"

# loop over all files in $dir2 because you want to find files in $dir2 that are not in $dir1
for file2 in "$dir2"/*
do
    # if $dir2 does not exist or is empty we will get something like file2="/C:/Users/shubham.tomar/Desktop/Shell/Test2/*" 
    # That's why check if the file exists
    if [ -f "$file2" ]
    then
        filename2=$(basename "$file2")
        echo $filename2
        echo "------------------------"

        # does a file with the same basename exist in $dir1?
        if [ ! -f "$dir1/$filename2" ]
        then
            # using "$targetdir"/." makes sure you get an error if $targetdir is a file instead of a directory
            mv -f "$file2" "$targetdir"/.
            echo "--------------File Moved-----------"
        else
            echo "file with the same name exists in $dir1"
        fi
    fi
done

If you want to try this first without actually moving files you can replace the line

        mv -f "$file2" "$targetdir"/.

with

        echo mv -f "$file2" "$targetdir"/.

Answer 2

sf() {
    # find all files in the directory $1 non-recursively and sort them
    find $1 -maxdepth 1 -type f printf '%f\n' | sort
}

Then run

join -v 1 <(sf Tes2) <(sf Tes1) | xargs -d '\n' -I file mv Tes2/file MovedFiles/

The left operand of the pipe finds all the files in Tes2 that are not in the directory Tes1.

The right operand of the pipe then moves those files to the directory MovedFiles.