How to use wc, grep and ls to list all files that are at least 10,000,000 bytes in a directory?

Question

Now I find that wc -c could show the size of file, then how to select them and list them? It should be a single pipeline of commands.

Note that using wc to find the sizes of really big files is just masochism. It would need to read the whole file and count each individual byte. The file size information is already stored as meta-data in the directory. — Kusalananda, Feb 11 '19 at 15:04
Better use the faster "du" command instead of "wc". du -b does the same as wc -c (output in bytes). — Freddy, Feb 11 '19 at 15:08

score 3 · Answer 1 · answered Feb 11 '19 at 14:59

3

find will be better:

find . -type f -size +9999999c

Replace . with the directory.

answered Feb 11 '19 at 14:59

Modified to also print the file sizes in bytes and sorted by file size (largest files first): find . -type f -size +9999999c -print0 | xargs -0 du -b | sort -nr – Freddy Feb 11 '19 at 15:16

1 Answers1