Bash script convert

Question

i need to convert the text below in bash script

111319 2036

to

11/13/19 20:36

it's possible?

regards.

Possibly duplicate: https://unix.stackexchange.com/questions/534033/how-to-restructure-a-date-variable-in-bash — Jim L., Nov 19 '19 at 01:04
It is possible. You'll use regular expressions and capturing parentheses, and put in the additional characters in the replacement part. — glenn jackman, Nov 19 '19 at 01:08
thanks, i got using: sed 's/^(.{2})(.{2})(.{2})(.{3})(.{2})/\1/\2/\3 \4:\5/g' — Lucas, Nov 19 '19 at 01:18
@Lucas the right place for an Answer is below, in the Answer box; thank you! — Jeff Schaller, Nov 19 '19 at 01:43

score 3 · Answer 1 · answered Nov 19 '19 at 01:22

3

With GNU awk:

awk -v FIELDWIDTHS='2 2 2 1 2 2' '{ print $1 "/" $2 "/" $3 " " $5 ":" $6 }'

answered Nov 19 '19 at 01:22

Thor

score 2 · Answer 2 · answered Nov 19 '19 at 03:02

The traditional solution would be to do something with sed

sed 's!^\(..\)\(..\)\(..\) \(..\)\(..\)!\1/\2\/\3 \4:\5!'

For example:

% echo 111319 2036 | sed 's!^\(..\)\(..\)\(..\) \(..\)\(..\)!\1/\2\/\3 \4:\5!'
11/13/19 20:36

There's also the possibility of a pure bash solution.

If, for example, you have the value in $a then

${a:0:2}/${a:2:2}/${a:4:2} ${a:7:2}:${a:8:2}

For example:

$ a="111319 2036"
$ echo ${a:0:2}/${a:2:2}/${a:4:2} ${a:7:2}:${a:8:2}
11/13/19 20:03

score 1 · Answer 3 · answered Nov 20 '19 at 14:31

1

echo "111319 2036"| awk '{print substr($1,1,2)"/"substr($1,3,2)"/"substr($1,5,2) " " substr($NF,1,2)":"substr($NF,3,4)}'

output

11/13/19 20:36

answered Nov 20 '19 at 14:31

Praveen Kumar BS

3 Answers3