How to trim last part of the string having delimiter?

Question

I have string(s) having delimiter underscore(_)

Input -

Expected output -

I want to remove only last part of the string. Can anyone suggest quicker way probably one-liner to achieve this?

Are the strings in a file? – Kusalananda May 28 '20 at 18:24 — Kusalananda, May 28 '20 at 18:24

score 2 · Accepted Answer · answered May 28 '20 at 17:58

2

string='ABC_TEST'
mod_string="${string%_*}"
echo "$mod_string"
ABC

answered May 28 '20 at 17:58

Hauke Laging

parameter expansion is nice, here's a link to some other PE tricks: http://mywiki.wooledge.org/BashGuide/Parameters#Parameter_Expansion – b0yfriend May 28 '20 at 18:14

score 1 · Answer 2 · edited May 28 '20 at 18:25

1

The basic sed command is:

sed 's/_TEST$//' filename

or, to remove anything after the last _:

sed 's/_[^_]*$//' filename

If the strings come from another command: command | sed ...

If it's a variable sed ... <<< "${VARIABLE}"

edited May 28 '20 at 18:25

Kusalananda

answered May 28 '20 at 17:58

André Werlang

I have tried this already as TEST can be any word. so better to use parameter expansion method – Rocky86 May 28 '20 at 18:10
@Rocky86 This has been fixed. See also https://unix.stackexchange.com/questions/169716 – Kusalananda May 28 '20 at 18:26

2 Answers2