when don't I give the argument to option, option is not working

Asked Jun 14 '20 at 00:52

Active Jun 14 '20 at 05:20

Viewed 92 times

example code:

function purge() {
delete_dir;
case $purge_arg in
       --static)
       delete_static_dir;
       ;;
   esac
}
while getopts ":nrp:h" opt; do
  case ${opt} in
    h ) guide;
      ;;
    n ) new_address;
      ;;
    r ) tor_server;
      ;;
    p )
      purge_arg=${OPTARG}
      purge
      ;;
  esac
done

problem:

./script.sh -p --static #it's work
deleting dir;
deleting static dir.
./script.sh -p  #It should run the delete dir command but it doesn't work

what should i do to make it run?

edited Jun 14 '20 at 05:20

asked Jun 14 '20 at 00:52

rojen

One problem: you call purge before setting purge_arg (on which purge depends) – Andy Dalton Jun 14 '20 at 03:12
sorry, it still doesn't work. Could it be because of the ":" operator's forced argument? – rojen Jun 14 '20 at 05:21
You can't both require that -p takes an argument and allow -p to not take an argument, if you use getopts. – Kusalananda Jun 14 '20 at 07:51

when don't I give the argument to option, option is not working

0 Answers0