How to loop netcat for each line of input?

Question

I am trying to send text log files to my remote syslog server. I need to be able to take a file, and for each line in that file (newline as the separator), send that line via netcat to a remote syslog host. I don't want the whole file to be sent in one connection as it will show in syslog as one massive blob. Also, I need to be able to execute this from the command line. I can't create a script and execute it.

For example, this sends the whole file in one blob (not what I want):

cat somemultilinefile | nc -u -w 0 syslogip 514

I have tried awk with system() and xargs, but have not found a combination that works. Any ideas?

Does this answer your question? Execute a command once per line of piped input? — thanasisp, Nov 29 '20 at 00:43

score 0 · Answer 1 · answered Nov 28 '20 at 21:17

0

So I have found this works:

cat somemultilinefile | while read -r line; do echo "$line" | nc -w0 -u syslog_server 514 ; done

Seems that there should be a better way but this gets it done.

answered Nov 28 '20 at 21:17

Michael Lines

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There is a better way, check the rsyslog module RELP. – Eduardo Trápani Nov 29 '20 at 01:52

How to loop netcat for each line of input?

1 Answers1