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I'm trying to write a program that can compute the average result given an integer N

 #!/bin/sh

CTR=0
sum=0
read N

while [ $CTR -ne $N ]; do
  read integer;
  sum=$(( $integer + $sum ))
  CTR=$(( $CTR + 1 ))
done 

printf '%.3f\n' "$(( $sum * 1/ $N ))"

This was my input when compiling :

2
5
6

Expected output 5.500

Actual output 5.000

Why is that ?

αғsнιη
  • 41,407
Samir
  • 133
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    Yes, integer arithmetic only in bash or sh. With ksh you would say float sum N, then the rest of the script should work as written. – glenn jackman Dec 22 '20 at 01:17
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    @Gaston there's no need to edit your question to include Answers; if your question is a duplicate, the Answers on that duplicate question are intended to answer this question as well. – Jeff Schaller Dec 22 '20 at 16:41

0 Answers0