0

Hello I am trying to execute a sh script via cronjob. My script:

#!/bin/bash
#!/usr/bin/expect -f

IP=$(hostname -I | awk '{print $2}')
echo $IP


echo "Verbindung zum Server aufbauen"

So what I am trying to do is, I need the IP of my Raspberry Pi and start a server via ssh. When I execute the script via terminal it works fine.

AdminBee
  • 22,803
matt
  • 1
  • Please present the code of your script using "code sample" formatting. Currently it's not clear how the script actually looks like - for example there is #!/bin/bash #!/usr/bin/expect -f on the first line, which seems obviously wrong. – raj Jan 20 '21 at 21:23
  • Welcome to the site. As you can see from some comments (where due to lack for formatting contributors misinterpreted your script has having two shebangs in the first line), please be sure to use the formatting tools when formulating your question. Also if you say "when I execute the script via terminal": Please edit your question to post the exact command-line (do you say ./script.sh , or bash script.sh, or whatever), and state which user you are when running the script via terminal. – AdminBee Jan 21 '21 at 10:01

1 Answers1

1

Using a double shebang might not work (#!/bin/bash #!/usr/bin/expect -f)

You need to set the PATH variable for cronjobs (see Where is cron's PATH set? )

This should work

#!/bin/bash
PATH=/usr/bin:/bin
hostname -I | awk '{print $2}' 
echo "Verbindung zum Server aufbauen"
Michael D.
  • 2,830