Execute second command only if first expression has value

Asked Apr 11 '21 at 15:46

Active Apr 11 '21 at 15:46

Viewed 271 times

I have global variable $MY_VAR.

How can I execute second command only if the variable has value:

echo $MY_VAR && echo "Show me only if variable $MY_VAR has value"

asked Apr 11 '21 at 15:46

artnikbrothers

1

Depends a bit on if you want to test if it's defined (but possibly empty), or if it has a nonempty value. Testing if a variable is empty in a shell script, How can I test if a variable is empty or contains only spaces?, How do I check if a variable exists in an 'if' statement? – ilkkachu Apr 11 '21 at 16:07
And also: http://mywiki.wooledge.org/BashGuide/TestsAndConditionals – ilkkachu Apr 11 '21 at 16:07
@ilkkachu Thanks for info! So there is no way to test if variable exists and it's not empty in command line? I don't need a bash script. Just want to execute a command if variable exists and it's not empty – artnikbrothers Apr 11 '21 at 16:10
1

The links @ilkkachu posted showed that there are several ways of doing what you want. e,g, echo $MYVAR ; [ -n "$MYVAR" ] && echo "show me only if..." – cas Apr 11 '21 at 16:27

0 Answers0