bash script, accessing pre-defined variables using for loop substitution

Asked Jun 30 '21 at 21:29

Active Jun 30 '21 at 22:27

Viewed 50 times

Heres the bash script:


ALL="2 3"
VC2="https://someaddress.acme.com"
VC3="https://someotheraddress.acme.com"
hosts2='12
13
14'
hosts3='15
16
17'
for i in $ALL
do

Here is where i want the substitution but no matter what i use it doesn't work. I tried all of the following

     VC="$VC$i"
     VC="${VC$i}"
     VC="$(VC$i)"
     VC=$(VC$i)
 HOSTS=&quot;$hosts$i&quot;
 echo &quot;$VC&quot;
 echo &quot;$HOSTS&quot;

the output i need is for each of the numbers in the ALL variable to then equal the predefined VC and hosts variables. i.e.

When i=2:

i=2
VC="https://someaddress.acme.com"
HOSTS='12
13
14'

and when i=3

i=3
VC="https://someotheraddress.acme.com"
HOSTS='15
16
17'

Thanks in advance.

Thomas

edited Jun 30 '21 at 22:27

asked Jun 30 '21 at 21:29

tom

You can use indirection / namerefs as described here Bash: Echo a variable whose name is the value of another variable however consider using indexed array variables instead. – steeldriver Jun 30 '21 at 22:16
1

Better, use arrays instead of splitting strings on either space or newline – Chris Davies Jun 30 '21 at 23:14
I did see the array route, i couldn't figure out how it was pertinent, i wasn't splitting anything. i am replacing variables!.. thanks. – tom Jul 01 '21 at 02:46
@steedrivers answer did the trick.. i saw references to arrays, but i couldn't get it to work for my example. – tom Jul 01 '21 at 02:58

0 Answers0