How to use multiple variable in bash

Question

I have a file (user.txt) with the below content with 90+ users

example file content

user: Ronaldo
id:7
endpoint:manutd.com
user: Messi
id:30
endpoint:psg.com
user: Neymar
id:10
endpoint:psg.com

desired output:

Ronaldo is in manutd.com and wears no 7
Messi is in psg.com and wears no 30
.
.

and so on for all the users

How can I print this way via a Bash script?

Does it have to be a bash script? Text-processing via shell loops is discouraged, as more efficient solutions exist. — AdminBee, Aug 30 '21 at 14:54

score 1 · Accepted Answer · answered Aug 30 '21 at 14:58

You can use this awk

awk -F: '/user/ {name=$2 " is in "; next} /id/{id="no "$2;next} /endpoint/ {team=$2 " and wears "} {print name, team, id }' $inputfile

Output

 Ronaldo is in  manutd.com and wears  no 7
 Messi is in  psg.com and wears  no 30
 Neymar is in  psg.com and wears  no 10

I am assuming your expected output with capitalization is wrong, but if not, please point this out.

score 1 · Answer 2 · answered Aug 30 '21 at 15:45

1

With sed:

$ sed -n 'N;N;s/^user: *\(.*\)\nid: *\(.*\)\nendpoint: *\(.*\)/\1 is in \3 and wears no \2/p' file
Ronaldo is in manutd.com and wears no 7
Messi is in psg.com and wears no 30
Neymar is in psg.com and wears no 10

answered Aug 30 '21 at 15:45

Stéphane Chazelas

544,893

score 1 · Answer 3 · answered Aug 30 '21 at 18:48

bash:

declare -A record
while IFS=":$IFS" read -r key value; do
    record[$key]=$value
    if [[ -v 'record[user]' && -v 'record[id]' && -v 'record[endpoint]' ]]; then
        printf '%s is in %s and wears no %s\n' "${record[user]}" "${record[endpoint]}" "${record[id]}"
        record=()
    fi
done < file.content

How to use multiple variable in bash

3 Answers3