How to echo "$$PARAMTER_NM=1234"

Question

How can I print $$PARAMTER_NM=1234 in a Linux shell? I am getting the PID of my current process with $$, so the output is like:

1943PARAMTER_NM=1234

But I need:

$$PARAMTER_NM=1234

See also How to use a special character as a normal one in Unix shells? — Stéphane Chazelas, Nov 25 '21 at 16:23

score 2 · Accepted Answer · answered Nov 25 '21 at 14:34

2

echo '$$PARAMTER_NM=1234'
$$PARAMTER_NM=1234

answered Nov 25 '21 at 14:34

Hauke Laging

score 1 · Answer 2 · edited Nov 25 '21 at 15:11

1

You can protect the contents of the string from the shell in two possible ways:

edited Nov 25 '21 at 15:11

Kusalananda

answered Nov 25 '21 at 14:36

Enrico

score 0 · Answer 3 · answered Nov 25 '21 at 14:34

0

# echo "\$\$PARAMTER_NM=1234"
$$PARAMETER_NM=1234

If you want to use a special/reserved character with double quotes (such as $) as-is - you need to use an escape character ('\') right before it.

answered Nov 25 '21 at 14:34

Alex

3 Answers3