How do I extract the filename from a path in Awk if I have different length filenames with a path?

Question

I have an Awk script that counts the average of rows from every file from a given directory and its subdirectories and I have to print the filename and the average from a file like this

example.c : 5

So I have filenames like this ../labor1/munka/hazik_pagi4188/hazik/c_prog/lab1/fork2.c and I want to get like this fork2.c (I have different length file names with path).

Why awk. basename is specifically designed for this. – doneal24 Jun 09 '22 at 12:47 — doneal24, Jun 09 '22 at 12:47
What do you mean by "count the average of rows"? – Kusalananda Jun 10 '22 at 09:51 — Kusalananda, Jun 10 '22 at 09:51

score 0 · Answer 1 · answered Jun 09 '22 at 09:37

0

Try "recursive" grep and remove the path with sed, like

grep -rc "." | sed 's#^.*/##'
madsum.awk:11
zmz.awk:14
file_to_process.txt:2

answered Jun 09 '22 at 09:37

RudiC

8,969

How do I extract the filename from a path in Awk if I have different length filenames with a path?

1 Answers1