removing Percentage symbol

Question

trying to remove percentage symbol '%' from this shell script

df -h | awk '$NF=="/"{printf "Percentage: %s \n", $5}'

output:

Percentage: 2% 

want to make the output like this

Percentage: 2

sorry for my bad english

Answer 1

Force the interpretation of the value in $5 as a numeric value. This can be done by adding zero to the value before printing it using the %s format:

df -h | awk '$NF == "/" { printf "Percentage: %s\n", 0+$5 }'

Or, by using %d to format the value as a decimal integer rather than as a string:

df -h | awk '$NF == "/" { printf "Percentage: %d\n", $5 }'

Or, explicitly delete the last character from the string before printing:

df -h | awk '$NF == "/" { printf "Percentage: %s\n", substr($5,1,length($5)-1) }'

df -h | awk '$NF == "/" { sub(".$","",$5); printf "Percentage: %s\n", $5 }'

Or, simply remove all % characters in the input:

df -h | tr -d % | awk '$NF == "/" { printf "Percentage: %s\n", $5 }'

df -h | awk '{ gsub("%","") } $NF == "/" { printf "Percentage: %s\n", $5 }'

Answer 2

And one more way to remove the % symbol:

df -h | awk '$NF == "/" { printf "Percentage: %s\n", int($5) }'