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The following script can only print -m but it can't print -n.

#!/bin/sh

echo $@

$ sh test.sh -m
-m
$ sh test.sh -n
$
ilkkachu
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haolee
  • 103
  • $@ doesn't print anything, and it deals with -n just fine, though you should be using "$@" instead; or maybe "$*" in this case. – ilkkachu Jul 29 '22 at 04:07

1 Answers1

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That's because -n is an actual option to echo. Most tools support -- to mean "there's no more options after this, just arguments", so try if using

echo -- $@

improves the situation.

Ulrich Schwarz
  • 15,989