How to take positional arguments in a function in zsh?

Question

I have a function defined as follows in my zshrc

function k8sapi() {
    PREFIX='https://STABLE_URL'
    if [ "$1" == "prod" ];
    then
        PREFIX='https://PROD_URL'
    fi
echo &quot;1 --&gt; $1&quot;
echo &quot;2 --&gt; $2&quot;
curl -s &quot;${PREFIX}/${2}&quot;

}

When I run this:

$ k8sapi stable foo
k8sapi:2: = not found

What am I doing wrong? How do I look at arguments to a function in zsh?

These functions were copied over from my old laptop using bash shell, so I am trying to migrate them to zsh.

score 2 · Accepted Answer · answered Sep 30 '22 at 22:22

2

The problem is with your if condition. You should use just one = or you can also use [[ condition ]].

 if [[ $1 == "prod" ]];
 then
    PREFIX='https://PROD_URL'
 fi

Or:

 if [ "$1" = "prod" ];
 then
    PREFIX='https://PROD_URL'
 fi

answered Sep 30 '22 at 22:22

Edgar Magallon

4,820

Thank you! Is that a ksh oddity? Why didnt it fail in bash? – feroze Sep 30 '22 at 23:26
@feroze In zsh, the = is an expansion. Try running echo =mkdir. This answer explains why zsh fails to use ==. (you can quoting "==" and it will work) – Edgar Magallon Sep 30 '22 at 23:46

How to take positional arguments in a function in zsh?

1 Answers1