ipsweep bash script not working (name or service not known)

Question

I coded a bash script for an ip sweeper however it keeps giving me ths "name or service not known" output. Here is the code :

And here is the output when I run the script :

Can you please help? I am relitively new to this but eager to learn

Please don't post pictures of text. Instead, copy and paste the text — Chris Davies, Oct 01 '23 at 19:50
As well, please show us exactly how you are running the script - in particular what argument(s) you are passing. FWIW, as posted, it looks like it should throw a "command not found" error because of the lack of whitespace after the [ - see for example Why are bash tests so picky about whitespace?. — steeldriver, Oct 01 '23 at 23:46
It looks like you're failing to specify the base of the IP range correctly. You specified "[10.0.2]". Do ./pingsweep.sh 10.0.2 instead. Also, read man ping and do sudo ping -c 1 -b 10.0.2.255 to do it all at once. — waltinator, Oct 02 '23 at 04:54
The problem is that the bash script reads the input with the brackets. For example, if I put bash .\ipsweep [192.168.1] il reads the input as [192.168.1] and if i do bash .\ipsweep 192.168.1 it gives me an error message — TomPps 1704, Oct 02 '23 at 12:58
Please don't post pictures of text. Instead, copy and paste the text so it's readable and testable — Chris Davies, Oct 02 '23 at 18:25

score 0 · Answer 1 · edited Oct 09 '23 at 07:22

0

This is what I think you want.

I replaced [ "$1" == ] with [ -z "$1" ], and no more errors.

#!/bin/bash
if [ -z "$1" ]
then echo "You forgot an ip address!"
    echo "Syntax ./ipsweep.sh 192.168.1"
else
    for ip in $(seq 1 254)
    do ping -c1 $1.$ip |grep "64 bytes"|cut -d " " -f4 |tr -d ":" |tee -a iplist.txt
done
fi
echo -e "\nComplete. Results can be found in the file iplist.txt"

I swapped out the 2nd ping line and replaced it with the tee command. It will print on the screen and into the iplist.txt file. Not to mention make your script run a lot faster.

edited Oct 09 '23 at 07:22

tinlyx

678

answered Oct 04 '23 at 04:39

Cyberninja

195

Oh I see what you changed. seq 1 254 is functionally the same as $(seq 1 254). Though $(seq 1 254) is the newer method. – Cyberninja Oct 04 '23 at 15:47
Hey thanks a lot for your response. I'll see if this works – TomPps 1704 Oct 05 '23 at 05:20
@TomPps1704 It should work I tested it before I posted it. – Cyberninja Oct 05 '23 at 05:29

ipsweep bash script not working (name or service not known)

1 Answers1