rename files's name in linux

Question

I need to rename 3028 files' names at once. Do you have any help?

0001____z1.0.tif    -->  0001.tif
0002____z2.0.tif    -->  0002.tif
   .
   .
   .
3028____z3028.0.tif --> 3028.tif

Can i rename whtout "____z2.0.tif" all files at once using the "rename" option for linux? or other way....? Please let me know if you have any idea. It would be grateful...

'using the "rename" option for linux' – Warning: the rename is not well-defined. See What's with all the renames: prename, rename, file-rename? and What are the different versions of the rename command? How do I use the Perl version? — Kamil Maciorowski, Oct 16 '23 at 04:42
I wrote an answer here about a similar question, I hope it can help you https://unix.stackexchange.com/a/759073/541313 — ramius, Oct 16 '23 at 11:58

score 0 · Answer 1 · edited Oct 16 '23 at 08:40

0

Using perl rename or prename:

rename 's/_.*/.tif/' *.tif

edited Oct 16 '23 at 08:40

Jeff Schaller

67,283
35
116
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answered Oct 16 '23 at 06:30

pLumo

22,565

sudo apt install rename if you are on a debian-derivative. – Stewart Oct 16 '23 at 06:36

qqqq · Answer 2 · 2023-10-17T15:45:32.300

Even though there is already an answer, I believe this task can be accomplished with just the shell.

Bash:

The expressions between the curly brackets are called brace expansions.

for fn in {1..3028}; do
    mv "$(printf "%04d\n" "${i}")____z${i}.0.tif" "${i}.tif"
done

POSIX:

i=0
while [ "${i}" -le 3028 ]; do
    mv "$(printf "%04d\n" "${i}")____z${i}.0.tif" "${i}.tif"
    i=$((i + i))
done

You may need to change into the directory where the files are or add its pathname to the arguments of the mv command. For example, if the files are in /tmp:

mv "/tmp/$(printf "%04d\n" "${i}")____z${i}.0.tif" "/tmp/${i}.tif"

rename files's name in linux

2 Answers2