How to make an alias command with argument

Question

I do not know what to use as the title for this question, but here is what I am looking for:

I find myself using the command below very often to find files within a subdirectory:

$ find ./ -type d -iname "*FILE*"

One way is to create a bash script with an argument and put it somewhere (e.g., /usr/bin).

But on some systems which I may not access those folders or maybe can not change the path,

Is there a way to create an alias?

Does this answer your question? In Bash, when to alias, when to script and when to write a function? — Stephen Kitt, Dec 11 '23 at 13:56
What argument is the title about? In your command there are five arguments. An alias simply replaces text with text, it can turn myfind into find ./ -type d -iname, thus myfind "*FILE*" will become find ./ -type d -iname "*FILE*". So yes, this looks like an alias taking an argument, but it's not; the "argument" is just a piece of text that doesn't get replaced and remains as-is. If you mean another argument then no, because the argument would need to appear in the middle of the resulting string. — Kamil Maciorowski, Dec 11 '23 at 14:16
You can place a script in a directory in your $HOME directory (typically $HOME/bin), and just add that to your $PATH. — larsks, Dec 11 '23 at 14:22
The answers to the duplicate should be enough (please let me know if they aren't). You are looking for something like adding alias my_find='find ./ -type d -iname "*FILE*"' to your ~/.bashrc. — terdon, Dec 11 '23 at 14:29

0 Answers0