Splitting stdin to different outputs in bash

Question

Possible Duplicate:
Is there a way in bash to redirect output and still have it go to stdout?

How would I send /dev/stdin to both /dev/stdout and a $logfile in one command?

One solution would be just to do it once for both:

 cat /dev/stdin > $tempfile;
 cat $tempfile > /dev/stdout;
 cat $tempfile > $logfile;

But that seems bad. Is there a better way?

I remember this question being ask before. – phunehehe Feb 23 '11 at 12:42 — phunehehe, Feb 23 '11 at 12:42
This is a duplicate. This is related. – phunehehe Feb 23 '11 at 12:53 — phunehehe, Feb 23 '11 at 12:53

score 7 · Accepted Answer · answered Feb 23 '11 at 10:49

7

The command tee is exactly doing this :

cat /dev/stdin | tee $logfile

answered Feb 23 '11 at 10:49

jon_d

1 Answers1